4x^2-9x-8=2x+1

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Solution for 4x^2-9x-8=2x+1 equation:



4x^2-9x-8=2x+1
We move all terms to the left:
4x^2-9x-8-(2x+1)=0
We get rid of parentheses
4x^2-9x-2x-1-8=0
We add all the numbers together, and all the variables
4x^2-11x-9=0
a = 4; b = -11; c = -9;
Δ = b2-4ac
Δ = -112-4·4·(-9)
Δ = 265
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{265}}{2*4}=\frac{11-\sqrt{265}}{8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{265}}{2*4}=\frac{11+\sqrt{265}}{8} $

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